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Free_Kalibri [48]
3 years ago
11

Watch help video

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

m= 6/-5

Step-by-step explanation:

m= y2-y1/x2-x1

m= 6-(-6)/-18-(-8)

m= 12/-10

m= 6/-5

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(WILL MARK BRAINLIST)
lawyer [7]

Answer:

3 or 4, I am confused

Step-by-step explanation:

I'll assume that f(x) = x2 – 2x + 8 is meant to be f(x) = x^2 – 2x + 8

Find the value of f(x) for x = 2:

f(x) = x^2 – 2x + 8

f(2) = (2)^2 – 2*(2) + 8

f(2) = 4 - 4 + 8

f(2) = 8

=============

From the graph, we can find that g(2) = 11

The differece between g(2) and f(2) is thus:

   11 - 8 = 3

3 is not an option, so I wonder if the question is asking for the difference between the absolute maximum of g(x) and f(2).  If so, the maximum for g(x) is 12, at x = 3.  

This would lead to a difference of 12 - 8, or 4.  This is still not an option, so I'm confused.  Perhaps you can find my error and find the ciorrect answer, or at least one that appears in the options.

4 0
3 years ago
Please help asap! <br> Which graph represents the function?
Alexandra [31]

Answer:

The below right one

Step-by-step explanation:

8 0
3 years ago
A sample of 200 college freshmen was asked how many hours per week they spent playing video games. The following frequency distr
JulsSmile [24]

Answer:

\% Below\ 50 = 88 \%

\% 43\ or\ more = 17 \%

Step-by-step explanation:

Given

Total = 200

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10

Frequency = 176

The percentage is then calculated as:

\% Below\ 50 = \frac{Frequency}{Total} * 100\%

\% Below\ 50 = \frac{176}{200} * 100\%

\% Below\ 50 = \frac{176* 100}{200} \%

\% Below\ 50 = \frac{176* 1}{2} \%

\% Below\ 50 = \frac{176}{2} \%

\% Below\ 50 = 88 \%

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

Frequency = 10 + 7 + 5+12

Frequency = 34

The percentage is then calculated as:

\% 43\ or\ more = \frac{Frequency}{Total} * 100\%

\% 43\ or\ more = \frac{34}{200} * 100\%

\% 43\ or\ more = \frac{34* 100}{200} \%

\% 43\ or\ more = \frac{34* 1}{2} \%

\% 43\ or\ more = \frac{34}{2} \%

\% 43\ or\ more = 17 \%

7 0
3 years ago
Un río tiene una corriente hacia el sur de 20 km/h, una lancha de motor cruza el río hacia el oeste a una velocidad de 50 km/h ¿
Semenov [28]

Answer:

english ?

Step-by-step explanation:

6 0
3 years ago
The length of an equilateral triangle is increased by 7 inches, so the perimeter is now 36 inches. Find the original length of e
STALIN [3.7K]
The original length is 5 inches per side.
4 0
4 years ago
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