Answer:
a) 1/4
b) 1/6
c) 1/12
Step-by-step explanation:
Let S be the sample space.
S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}
n(s) =12
<em><u>Events </u></em>
A: coin with head and die with prime number .
B:coin with head and die with composite number.
C:coin with tail and die with even prime number.
a) A={H2,H3,H5}
n(A) = 3
P(A) =n(A)/n(S)
=3/12
= 1/4
b) B={H4,H6}
n(B)= 2
P(B) = n(B)/n(S)
= 2/12
= 1/6
c) C ={T2}
n(C) = 1
P(C) = n(C)/n(S)
= 1/12