The answer is 4c-10
10 + 25 (35) is less than 40 - 10 (30)
For these you just plug in the value given for the variable (in this case, c) to each choice until you find the one is true
Assuming that you mean the log_(base 3)

, change the square root into an exponent: log(base 3)3^1/2. Then, because of how logarithms work, the answer simply is 1/2.
The first thing you should do for this case is to rewrite the expression.
To do this, divide both sides of the equation between -3.
We have then:
(-1/3) * (- 3x ^ 4 + 27x ^ 2 + 1200) = (- 1/3) * (0)
x ^ 4-9x ^ 2-400 = 0
Then, we rewrite the polynomial:
(x-5) * (x + 5) * (x ^ 2 + 16) = 0
From here, we obtain the four roots:
Root 1:
x-5 = 0
x = 5
Root 2:
x + 5 = 0
x = -5
Root 3 and root 4:
x ^ 2 + 16 = 0
x3 = -4i
x4 = 4i
Answer:
all the zeroes of the equation are:
x1 = 5
x2 = -5
x3 = -4i
x4 = 4i
Answer:
200 oz
Step-by-step explanation:
Just use the equation
0.32x=200
The graph of the functions f(x) and g(x) are the same
<h3>The sketch of the graph of the function</h3>
The function is given as:
f(x) = log₂(x)
See attachment for the sketch of the graph.
<h3>The domain of f</h3>
From the graph, we can see that the x values are greater than 0
This means that the domain of f is x > 0
<h3>The equation of f⁻¹(x)</h3>
We have:
f(x) = log₂(x)
Rewrite as:
y = log₂(x)
Swap x and y
x = log₂(y)
Express as an exponential function
y = 2ˣ
So, we have:
f⁻¹(x) = 2ˣ
Hence, the equation of f⁻¹(x) is f⁻¹(x) = 2ˣ
<h3>The
asymptote of f⁻¹(x)</h3>
We have:
f⁻¹(x) = 2ˣ
Set the function to 0
f⁻¹(x) = 0
Rewrite as:
y = 0
Hence, the asymptote of f⁻¹(x) is y = 0
<h3>How to plot the graph of g(x)?</h3>
We have:
f(x) = log₂(x)
g(x) = log₂(x)
Both equations are the same.
Hence, the graph of f(x) and g(x) are the same
Read more about logarithmic functions at:
brainly.com/question/3181916
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