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mina [271]
3 years ago
5

I need help idk how to solve this plz help. y - 2= 7/3 (x-(-2))

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Im sure it's -3    Because well thats what  i got

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Using the substitution P=1/x and Q=1/y.
erma4kov [3.2K]

Step-by-step explanation:

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3 years ago
Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).
alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))=C\cdot Sum of diagonal elements of A

C(Tr(B))=C\cdot Sum of diagonal elements of B

C(A+B)=C\cdot (A+B)

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]

B=\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

A+B=\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]

C(A+B)=\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

5 0
4 years ago
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irinina [24]

Answer: Scale factor of -1/2

Step-by-step explanation:

B=A*(-2)

A=B/(-2)

A=-(B/2)

A=B*(-1/2)

Scale factor of -1/2

7 0
1 year ago
Use the horizontal number line shown to answer the question. Which statements are true? Check all that apply. a.–9 < –7 b.–6
Mariulka [41]

Answer:

Its A and C trust me

Step-by-step explanation:

I got it right on edg 2021 sorry if i'm late

8 0
3 years ago
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ryzh [129]
2/5
2 out of 5
means 2/5
or 4/10, whichever
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4 years ago
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