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Rus_ich [418]
3 years ago
11

Which expression has a value of 15 when n = 7?

Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Answer:

19-\frac{28}{n}<em> is the expression with the value of 15 when n = 7</em>

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

43-5n

Substitute the value of n & simplify,

43-5(7)

43-35=8

Since the value of the expression is 8 which is not equal 15.

Hence expression 43-5n does not have value of 15 when n = 7.

Expression 2:

3n-5

Substituting the value of n & simplify,

3(7)-5

21-5=16

Since the value of the expression is 16 which is not equal 15.

Hence expression 3n-5 does not have value of 15 when n = 7.

Expression 3:

6n-28

Substituting the value of n & simplify,

6(7)-28

42-28=14

Since the value of the expression is 14 which is not equal 15.

Hence expression 6n-28 does not have value of 15 when n = 7.

Expression 4:

19-\frac{28}{n}

Substituting the value of n & simplify,

19-\frac{28}{7}

19-4=15

Since the value of the expression is 15 which is equal 15.

Hence expression 19-\frac{28}{n} has the value of 15 when n = 7.

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Step-by-step explanation:

Given the Population proportion 'P'= 16% = 0.16

Given data a department store in a certain city sampled 80 items sold in January and found that 24 of the items were returned

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here x =24 and n = 80

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a)<u> Point estimate</u>:-

A point estimate of the true proportion P

Point estimate = p = \frac{x}{n}

point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

p = \frac{x}{n} = \frac{24}{80} = 0.3

b) <u>The 95%  confidence interval for the proportion </u>

The 95% confidence interval for the proportion of returns at the store in the given city

(p - z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p + z_{\alpha }\sqrt{\frac{p(1-p)}{n} } )

substitute all values we get ,

(0.3 - 1.96 \sqrt{\frac{0.3(1-0.3)}{80} } , 0.3 + 1.96\sqrt{\frac{0.3(1-0.3)}{80} } )

on simplification, we get

(0.3-0.10042 ,0.3+0.10042)

( 0.19958,0.40042)

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Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

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