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mojhsa [17]
3 years ago
12

i’ll give you all my points that i have and rate you good if you answer these three questions before 3:00pm est. if f(x)=8-5x, f

ind each value. one is f(4c), the second question is f(2-k), and the third is f(4p+3)
Mathematics
1 answer:
maks197457 [2]3 years ago
8 0
Ok so to start you plug in what’s in the parentheses for x

4c=8-5(4c)
2-k=8-5(2-k)
4p+3=8-5(4p+3)

In the first one you distribute the -5
4c=8-20c
Then add 20c to both sides
24c=8
And divide by 24
C=8/24 or 1/3

Distributing the -5 on the second one gets you
2-k=8-10+5k
Then you combine like terms
2-k=-2+5k
Subtract 5k from both sides
2-6k=-2
Subtract 2 from both sides
-6k=-4
Divide by -6
K=4/6 or 2/3

and lastly the equation is 4p+3=8-5(4p+3)

So you distribute -5
4p+3=8-20p-15
Combine like terms
4p+3=-20p-7
Add 20p to both sides
24p+3=-7
Subtract 3 from both sides
24p=-10
And then divide by 24
P= -10/24 or -5/12
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5(-3x - 2) - (x - 3) = -4 (4x +5) + 13
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Start off by distributing the numbers into the parentheses:

5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
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