Answer:
10.28425
Step-by-step explanation:
The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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Answer:
x-intercepts: (2,0), (4,0)
y-intercepts: (0,-8)
Explanation:
To find the x intercept(s), you must compute where y=0. So solve 0= -x^2 + 6x - 8. So, the x intercepts are: (2,0) and (4,0) since the solutions to the mentioned equation are x=2 and x=4. To find the y intercept(s) compute what is y when x=0. In this case, when x=0, y=-8. So the only y intercept is (0,-8).
Answer:
(
1
,
∞
)
Step-by-step explanation:
Interval notation rounds up to infinite