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Rashid [163]
3 years ago
8

PowerPoint is a visual aid for many speakers. Discuss some points to remember when adding text to a PowerPoint presentation. How

do they help make the experience better for the audience and the presenter? What things can you do when creating a PowerPoint presentation to assure that your work adds to the speaker’s presentation without detracting attention from the speaker?
Computers and Technology
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

Use a lot of spinning animations to draw attention. Use many colors. A lot of text so you can read from the slide in case you get lost.

You might be interested in
Q. Describe the T.V. as an ICT tool.​
Vikentia [17]

Answer:

TV or modern televisions are also a type of ICT tool because we get a wide amount of information about mass communication through the various news channels on the TV. TV is now also the most popular as well as a cheap medium of mass communication.

3 0
3 years ago
What method of the Math object can be used to return the largest value from the values that are passed to it?
miss Akunina [59]

Answer:

the Math.max() method

Explanation:

The java.lang.* package contains all the essential components needed for a JAVA program which involves numbers and all the operations done on the numericals.

The java.lang.math class contains all the methods needed to perform mathematical operations on numerical values.

All the methods in the question are discussed below with examples.  

Math.max() method

java.lang.Math.max(double/ int/ float a, double/ int/ float b)

This method returns the highest value from among the parameters passed to it.

The syntax for the above is  

Numbers can be integers, float and double or long. The return type is the same as the parameters.

Two values to be compared are passed as arguments and the higher value of them is returned.

This function also accepts negative integers as parameters.

Math.max(-9, -2);

Gives -2 as the output.

Math.max(0.34, 0.45)

Gives 0.45 as the output.

Math.ceil() method

java.lang.Math.ceil(double/ int/ float a)  

This method returns the nearest greater whole number for the given number.

Integer parameter returns an integer number.

Math.ceil(7);

Gives 7 as the output.

Decimal number will return the nearest higher integer.

Math.ceil(8.7);

Gives 9.0 as the output.

Math.ceil(-0.34)

Gives -0 as the output.

Math.pow() method

java.lang.Math.pow(double/ float/ int a, double/ float/ int b)

The above method returns the result of a raise to the power of b.

The first parameter is the base while the second parameter forms the exponent.

Math.pow( 2.3,  4.5 );

This calculates (2.3)^4.5.

Gives 42.44‬ as the output.

Math.pow( 2, 3 );

This calculates the value of 2^3.

Gives 8 as the output.

Math.abs() method  

java.lang.Math.abs(double a)

This method returns non-negative value of the numerical parameter passed to it. Absolute of a number does not changes its value but changes the sign of a negative number. It returns the positive or negation of the negative input number.

Math.abs(-0.1234)

Gives 0.1234 as the output.

Math.abs(12.34)

Gives 12.34 as the output.

These methods require java.lang.Math to be imported in the program.

7 0
4 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
4 years ago
When using a public computer or network, you should always _______.
yaroslaw [1]
When using a public computer or network, you should always browse appropriately and log out of personal accounts when you're done. 
6 0
3 years ago
Read 2 more answers
Which computer career field enables you to create and design interactive multimedia products and services?
rjkz [21]
I think its graphic design
3 0
4 years ago
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