If both printers work together. Then the number of the pamphlets will be 20x in four hours.
<h3>What is Algebra?</h3>
Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.
A local print shop has a big order of pamphlets to print, so they decide to use two of their printers for the one job.
The newest printer can print the pamphlets four times as fast as the old printer Working together the printers can complete the job in 4 hours.
Let x be the number of the pamphlets are printed by the old printer in one hour.
Then the number of the pamphlets are printed by the new printer in one hour will be 4x.
Then if they work together, then the number of the pamphlets in one hour will be 5x.
Then the number of the pamphlets in 4 hour will be
→ 5x × 4
→ 20x
More about the Algebra link is given below.
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SOLUTION:
A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).
Answer:
70
Step-by-step explanation:
We have the final part 4x/40 = 7. We can simplify this to x/10 = 7 by dividing the numerator and the denominator by 4. We then multiply both sides by 10 to get x = 70
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
Answer:
c
Step-by-step explanation:
plot your graph and then you will see there is no line which shows there is a correlation. they're too scattered
