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astraxan [27]
3 years ago
5

Find missing size if side of right angled triangle

Mathematics
1 answer:
Vsevolod [243]3 years ago
8 0

Answer:

ABC is a right angled triangle with BC = 6 cm and AB = 8 cm. AC ... A line drawn from center of the circle will be perpendicular to the sides of the triangle ... be same which ever be the base. 1/2 * 8 *6= 1/2 * 10 * h (h= the altitube drawn to the hypotenuse) h= 4.8. ... As sides BC=6 am and AB = 8 cm, we can derive AC=10 cm

Step-by-step explanation:

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For the function h(x) =3x/(x+5)(x-4), solve the equation.​
LuckyWell [14K]

Answer:

x = 0

Step-by-step explanation:

To 'solve' means to find the x values that make the equation equal zero, so

0 = (3x)/[(x + 5)(x - 4)  

Multiply both sides by the denominator to get rid of the fraction

0[(x + 5)(x - 4)] = [(3x)(x + 5)(x - 4)]/[(x + 5)(x - 4)]

0 = 3x  

 0 = x     (divide both sides by 3)

So x = 0 is the solution for this equation

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2 years ago
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8 0
3 years ago
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4 0
3 years ago
OC and OR are similar. Find the length of QP.
Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is s = \frac{22 \pi}{9}

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s,  r and \theta is

arclength = 2\pi r \frac{\theta}{360}

where,

s be the length of the arc

r be the radius

\theta be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}

or, 2r \frac{\theta}{360} = \frac{22}{9} [ eliminating \theta from both side]

or, \theta = \frac{(22)(360)}{(9)(2)(4)}

or, \theta = 110^\circ

Again,

For circle R

Taking, r = 6 and \theta = 110^\circ we get,

The length of arc QP is

arc length = 2\pi (6)(\frac{110}{360} )

or, arclength = \frac{11 \pi}{3}

Hence,

The length of QP is \frac{11 \pi}{3}. Option C.

5 0
3 years ago
The distance from jason's house to school is 0.5 meters. What is the distance in meters?
Lady_Fox [76]
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HOPE THIS helps you !!
6 0
3 years ago
Read 2 more answers
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