The answer would be: Go on a vacation that costs $3,500
Paying off money for buying a car will not decrease your net worth as you get the car as assets for the money you use. But the depreciates 20% will cause you to lose $3,000 assets. Assuming you are not buying assets at all, go on a vacation that costs $3,500 will increase liability without any effect on assets. Paying up bills will decrease your asset but it also decreases your liability so the net worth wouldn't change.
Is one of the answers thumbnail? If so, select it.
The principles of creating equations are the same in
PowerPoint 2007 and later. Assuming Danny is using PowerPoint 2010, he will
click on the insert tab then go ahead and choose the Equation in the symbols
group.
Dani will be able to click on the equation option and use the Equation
Tools Design tab or click on the drop down arrow to view more equations
Answer:
True
Explanation:
When using databases in a project, not everyone has the same access level, e.g the database admin may have the highest level of access (access to data on live mode), the software testers have their own level of access (access to data on test mode) and so on.
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
