The answer is A!! Your welcomeeee
Answer:
The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E
Step-by-step explanation:
* Lets explain what is the class mid-point
- It is defined as the average of the upper and lower class limits
- The class midpoint is the lower class limit plus the upper class limit
divided by 2
- The easiest way to find the class mid-point is to add the upper
and lower boundary and divide your answer by two
- The lower limit for every class is the smallest value in that class.
- The upper limit for every class is the greatest value in that class
* <u><em>Lets solve the problem</em></u>
- It is not the largest value of that class minus the class width
- Its not the difference between the largest and smallest values of
that class
- It is not the difference between the largest and smallest values of
that class divided by 2
- It is the center of that class, which is the sum of its largest and
smallest values divided by 2
Answer:
I answered it
Step-by-step explanation:
I answered it
Answer:
7
Step-by-step explanation:
Given that there are 5 number cards.
They are 2,5,7,8,9
Total of all numbers in the cards = 2+5+7+8+9= 31
One card is removed say with number x.
Now sum new would be =31-x .. i
Average of remaining 4 cards = 6
So sum of remaining 4 cards = 6(4) = 24 ... ii
i and ii represent the sum of remaining 4 cards. Hence they should be equal
31-x =24
Subtract 31 from both sides to get
-x=-7
Or x =7
