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Temka [501]
3 years ago
7

Expand and simplify 2/5(p+15)-1/3(9+6p)+4/5p

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0
2/5p+6-3-2p+4/5p
-2p+6/5p+6-3+4
-10/5p+6/5p+3+4
-4/5p+7
-0.8p+7

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4 0
3 years ago
If the sum of the legs of a right triangle is 49 inches and the hypotenuse is 41 inches, find the length of the other two sides
german
The length of one leg is x inches.
The sum of the legs is 49 inches, so the length of the other leg is 49-x inches.
The length of the hypotenuse is 41 inches.

Use the Pythagorean theorem:
(\hbox{one leg})^2 + (\hbox{the other leg})^2=(\hbox{hypotenuse})^2 \\ x^2+(49-x)^2=41^2 \\&#10;x^2+2401-98x+x^2=1681 \\&#10;2x^2-98x+2401=1681 \ \ \ |-1681 \\&#10;2x^2-98x+720=0 \\ \\&#10;a=2 \\ b=-98 \\ c=720 \\ b^2-4ac=(-98)^2-4 \times 2 \times 720=9604-5760=3844 \\ \\&#10;x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-98) \pm \sqrt{3844}}{2 \times 2}=\frac{98 \pm 62}{4} \\&#10;x=\frac{98-62}{4} \ \lor \ x=\frac{98+62}{4} \\&#10;x=\frac{36}{4} \ \lor \ x=\frac{160}{4} \\&#10;x=9 \ \lor \ x=40

&#10;49-x=49-9 \ \lor \ 49-x=49-40 \\&#10;49-x=40 \ \lor \ 49-x=9

The lengths of the legs are 9 inches and 40 inches.
4 0
4 years ago
The legs of a right triangle measure 8 cm and 6 cm respectively. How long is the longest side of the triangle?
Masja [62]

Answer:

b. 10

Step-by-step explanation:

Based on the Pythagoras Theorem, the longest side of a right-angled triangle is: \sqrt{a^{2}+b^{2} } where a and b are the legs of the triangle.

Longest side of triangle = \sqrt{8^{2}+6^{2}}

                                        = \sqrt{64+36}

                                        = \sqrt{100}

                                        = 10

5 0
3 years ago
Find the z value of 97 when the mean is 75 and the standard deviation is 12
aksik [14]

Answer: 1.83

Step-by-step explanation:

Z = (x - mean) / standard deviation

= (97-75) / 12

= 22/12 = 11/6 = 1.83

3 0
4 years ago
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