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Scorpion4ik [409]
2 years ago
13

Ernest wants to buy 21 new books for his book collection. If the average price for a

Mathematics
2 answers:
lukranit [14]2 years ago
3 0

Answer:

If each book cost $20.45 then you times it by 21 and the answer you would get is 429.45

Step-by-step explanation:

im 99% that its correct

klasskru [66]2 years ago
3 0

Answer:

He should expect to spend as much as 429.45 (to be exact)

Step-by-step explanation:

It's really just simple math $20.45 multiplied by 21 is 429.45 (:

I'm sorry if I'm wrong. Have a great day and good luck!

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MrRissso [65]
3/3=1 and 7/8 is < 1 so 3/3 is bigger
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First person gets brainliest 3
ser-zykov [4K]

Answer:

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3 years ago
Read 2 more answers
The largest z-score available in most tables is 2.99, which corresponds to a probability of 99.86%. A fair coin is
lana66690 [7]

Answer:

The number of heads observed is 121.14 heads

Step-by-step explanation:

The formula for the z-score of a proportion is given as follows;

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{pq}{n}}}

Where:

{\hat{p} = Sample proportion

p = Population success proportion = 0.5

q = 1 - p = 1 - 0.5 = 0.5

n = Number in of observation = 200

z = 2.99

Hence, we have;

z=\dfrac{\hat{p}-0.5}{\sqrt{\dfrac{0.5 \times 0.5}{200}}} = 2.99

Therefore;

{\hat{p}-0.5}{} = 2.99 \times \sqrt{\dfrac{0.5 \times 0.5}{200}} = 2.99 \times\dfrac{\sqrt{2} }{40}

{\hat{p} = 0.6057

Whereby \ \hat p = \dfrac{Number \ of \ heads}{Number \ of \ observation} =  \dfrac{Number \ of \ heads}{200} = 0.6057

∴ The number of heads observed = 200 × 0.6057 = 121.14 heads.

5 0
3 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
URGENT!!!! Find the value of x. Round to the nearest degree
Kay [80]
To be exact it would be 27.8 but the nearest would be 33 degrees so the answer is A
6 0
3 years ago
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