Answer:
The process of cellular respiration allows plants to break down glucose into ATP.
Explanation:
Although plants use photosynthesis to produce glucose, they use cellular respiration to release energy from the glucose.
1. moisture/water
2. precipitation
3. evaporation
4.transpiration
5. warmer, more
6. vaporization
7. condensation nuclei
Answer:
<h2>D. Radioactive nitrogen in the DNA of the bacterial cells is present in one strand of the DNA of all of the cells.</h2>
Explanation:
As given here,
The nitrogenous base of DNA is radio active labeled, and is grown in normal unlabeled medium.
As we know that DNA replication occurs in semi-conservative way, so after one round of replication, one parental strand would be radio active and other newly synthesized strand would be unlabeled.
So here, after one round of replication, one strand of all the newly synthesized DNA would be radio active and other strand would be normal.
Answer:
In the semi-conservative method of DNA replication, each of the strands of the double helix acts as a template for replication.
Explanation:
Semi-conservative DNA Replication:
- Semi-conservative DNA replication produces two daughter helices from the original parent helix. One strand of the daughter helix is form the original template while the other is newly synthesized.
- This means that one strand will have the base sequence identical to the parent, while the other will be complementary to the template.
- This model was experimentally confirmed by an experiment conducted in 1958 by Meselson and Stahl. They used radioactive isotope of nitrogen i.e. N-14 or N-15. DNA molecules made with N-15 were allowed to replicate in the presence of N-14.
- After first replication, DNA molecules contained both N-15 and N-14 isotopes, disproving the conservative model that stated that the new helices are completely identical to the template.
- The second replication yielded only N-14 which disproved the dispersive model that the new helices are a combination of both the template and new strands.
Answer:
Polypeptides are composed of amino acids, and we know amino acids are differently charged, have different R groups, and also have different isoelectric points. Depending on different isoelectric points and charged groups, the polypeptides can be separated and because a protein has its lowest solubility on its isoelectric point.
So in this question,
(a) (Lys-Ala)3 ; this is highly positively charged (polar) at pH 7 than (Gly)20 which is uncharged except for the amino and carboxyl terminal.
(b) (Glu)20 ; it is highly negatively charged at pH 7 whereas (Phe-Met)3 is much less polar and hence less soluble.
(c) (Asn-Ser-His)5 ; at pH 3, because in (Ala-Asp-Gly)5 the carboxylate groups of Asp residues are partially protonated and neutral, whereas in (Asn-Ser-His)5 , the imidazole groups of His residues are fully protonated and positively charged.
(d) (Asn-Ser-His)5; at pH 6.0; both polymers have polar Ser sidechains, but (Asn-Ser-His)5 also has the polar Asn side chains and partially protonated His side chains.
Explanation:
