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3 years ago

In which table is Y a nonlinear function of X?

Mathematics

2 answers:

maxonik [38]3 years ago

4 0

Step-by-step explanation

Arte-miy333 [17]3 years ago

3 0

Answer:

The answer is A

Step-by-step explanation:

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Lucy's final exam has true/false questions, worth 2 points each, and multiple choice questions, worth 3 points each. Let x be th

Bad White [126]

True/False questions = 2 points each(x).
Multiple choice questions = 3 points each(y).
She needs more than (>) 90 points.

2x + 3y > 90

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What is 66 2/3% of 39

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Number x percent turned into decimal

39 x 0.666666666 = 26

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3 years ago

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When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.688

(e) The probability that none of the 25 boards is defective is given by = P(X = 0)

P(X = 0) = $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}$

= $1 \times 1\times 0.95^{25}$

= 0.277

(f) The expected value of X is given by;

E(X) = $n \times p$

= $25 \times 0.05$ = 1.25

The standard deviation of X is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{25 \times 0.05 \times (1-0.05)}$

= 1.089

8 0

3 years ago

If you apply for a job with Globo Corp, there is a 75% chance that you will get an interview.

aivan3 [116]

Answer:

The probability that you will get the job If you apply for a job with Globo Corp=0.36

Step-by-step explanation:

We are given that

If you apply for a job with Globo Corp, then the probability of getting interview P(A)=75%=0.75

If you get an interview, then the probability of getting job=P(B)=48%=0.48

We have to find the probability that you will get the job If you apply for a job with Globo Corp.

If you apply for a job with Globo Corp, the probability of getting job= $P(A)\times P(B)$

If you apply for a job with Globo Corp, the probability of getting job= $0.75\times 0.48$

If you apply for a job with Globo Corp, the probability of getting job=0.36

Hence, the probability that you will get the job If you apply for a job with Globo Corp=0.36

6 0

3 years ago

I need help please help me

Varvara68 [4.7K]

Answer:

I found x for you, right there.

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3 years ago

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