Which graph shows a system of equations with infinitley many solutions

El precio de costo de “x” artículos es 60x + 4 000, además el precio de venta de los mismos es 80x. Determinar la cantidad de ar

Citrus2011 [14]

Answer:

800 artículos.

Step-by-step explanation:

Sea x = la cantidad de artículos vendidos

De la pregunta,

Precio de costo = 60 x + 4000

Venta (precio de venta) = 80x

También nos dieron ganancias como S12000

Para determinar la ganancia

Precio de venta: precio de costo = beneficio (cuando el precio de venta es más alto que el precio de costo)

Por lo tanto,

12,000 = 80x - (60x + 4000)

12,000 = 80x - 60x - 4000

Recolectando términos similares

12,000 + 4,000 = 80x - 60x

16,000 = 20x

x = 16,000 / 20

x = 800

Por lo tanto, la cantidad de artículos que se venderán si desea obtener una ganancia de S12,000 es de 800 artículos.

7 0

3 years ago

Use the commutative law of MULTIPLICATION to write an equivalent expression.<br><br> 9(x+5)

DochEvi [55]

9x+45
!!!!!!!!!!!!!!!!!!!

6 0

3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Point P is the center of the circle below. What is the exact area

Ber [7]

Answer:

192π unit²

Step-by-step explanation:

Given that :

Radius = 24

Area of circle = πr²

Area = π*24²

Area = 576π in²

The Shaded area is 120°

Entire Circumference = 360°

Hence, shaded area = 120°/ 360° = 1/ 3 of the area

1/3 * 576π in²

= 192π unit²

5 0

2 years ago

Find the value of the expression below for x=10<br><br> x ^2 - 2 (x + 5)

Thepotemich [5.8K]

Answer:

20

Step-by-step explanation:

your welcome!!

7 0

3 years ago

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