Answer:
<h3>19,133.067</h3>
Step-by-step explanation:
Volume of the ball (spherical in nature) Vb = 4/3πrb³
Volume of the hole Vh = 4/3πrh³
rb is the radius of the ball
rh is the radius of the hole
If a ball of radius 17 has a round hole of radius 7 drilled through its center, the volume of the resulting solid will be expressed as:
V = Vb - Vh
V = 4/3πrb³ - 4/3πrh³
factor out the like terms;
V = 4/3π(rb³-rh³)
Given
rb = 17
rh = 7
V = 4/3π(17³-7³)
V = 4/3π(4913-343)
V = 4/3π(4570)
V = (4π*4570)/3
V = 57,399.2/3
V = 19,133.067
Hence the volume of the resulting solid is 19,133.067
I believe that the answer would be 27%
A cube has 4 "space" diagonals or diagonals within the cube's interior.
On its surface, a cube has 12 "face" diagonals, 2 per each of its six congruent square faces.
So the total number of diagonals is 4 + 12 = 16
5000000+900000+2000+700+30+1
=5900000+2000+700+30+1
=5902000+700+30+1
=5902700+30+1
=5902730+1
=5902731
five million,
nine hundred two thousand, seven hundred thirty-one
(Word form)
x = ± 3√6
2x² - 6 = x² + 48 ( subtract x² from both sides )
x² - 6 = 48 ( add 6 to both sides )
x² = 54 ( take the square root of both sides )
x = ± √54 = ± 3√6
