Answer:
first one
Step-by-step explanation:
We know that AB is a perpendicular bisector of IK.
Therefore point J is the midpoint of IK.
AJ = BJ Could be but based on the given information we cannot conclude it.
IJ = IK True.
A is the midpoint of IK. Wrong. J is the midpoint of IK.
Answer:
IJ = IK
Answer 74. y=2x
a) The line passes thought the origin, This is true.
if x=0 ⇒y=2*0=0 then , the line passes thought the origin (0,0).
b)On the line the value of eche abcissa is twice the value of its corresponding ordenate, this is false.
if x =2 ⇒y=4, therefore on the line the value of each abcissa is half the value of its corresponding ordenate.
c)The line has a slope of 2; this is true
m=2
d)The line is parallel to a line passing throught point (1,-3) (3,1) this is true, because the slope is the same.
Given two points (x₁,y₁) and (x₂,y₂) the slope is:
m=(y₂-y₁) / (x₂-x₁)
inThis case:
m=(1+3) / (3-1)=4/2=2
Answer:b)On the line the value of eche abcissa is twice the value of its corresponding ordenate. This is not true
Recall that the centroid of a triangle (the point where the three medians intersect) divides each median into parts in the ratio 2:1, with the
centroid being twice as close to the midpoint of a side as it is to the
opposite vertex.
Thus, the ratio of segment EG to segment BG is 1 : 2
Therefore, given that segment EG = 27 in, then segment BG = 2(27) = 54 in. and segment BE = 27 + 54 = 81 in.