All categories

2 years ago

Which of the following points is not coplanar with polnis C, D and E?

Mathematics

1 answer:

Leokris [45]2 years ago

7 0

Answer: Point R

===================================================

Explanation:

The term "coplanar" means "points that are in the same plane".

Points A, S and U are all in the base plane. Think of this as the floor of the pyramid, so to speak. These three points are with C, D, and E, which are also on the base plane or floor plane. So we can say that all of these points are coplanar.

In contrast, point R is not on the floor plane. It's higher up. So that's why R is not coplanar with points C,D,E.

You might be interested in

How can I fiure out markup from a price and a percent? (So if i have $1.50 and I need 20% more how do I do that)

Ede4ka [16]

1.50 + (1.50 * (20%)) = 1.8

7 0

2 years ago

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

2 years ago

Alot of people text me and say "hey bbg" and "bbg you fine"

Semenov [28]

Answer:

bbg means Babygirl

Step-by-step explanation:

It is a compliment/petname. It is meant to call a girl cute, or if you want to address someone in a flirty way. That's the best way i can explain it lol

8 0

2 years ago

Read 2 more answers

I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct

joja [24]

*If you need me to do #5, DM me!

3. The area of a triangle can be given by (just plug and chug as always):
$A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2$
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
$A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2$
$A_r = bh = 12(8) = 96m^2$
Now we just add them:
$96+12 = 108m^2$

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
$A_t = \frac{1}{2}bh$
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
$A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2$
Multiply by 4 to get total area:
$6.25*4 = 25cm^2$

So, the area of the given rhombus is 25cm².

8 0

3 years ago

The area of the square hole is 8 square centimeters. The volume of a cube shaped block is 64 cubic centimeters. Which edge lengt

damaskus [11]

case a) The area of the square hole is 8 square centimeters

we know that

the area of a square is equal to

$A=b^{2}$