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mina [271]
2 years ago
11

Tell me what I passed and what u didn’t pass please ASAP

SAT
2 answers:
cestrela7 [59]2 years ago
8 0

Answer:

Explanation:

To pass the College Readiness Benchmark, you must get:

ELAR: A score in the range of 945–990 on the ELAR CRC Test and a score of at least 5 on the Essay Test;

or an ELAR  CRC Test score below 945 and an ELAR Diagnostic Test  score of 5 or 6 and an Essay Test score of 5 or higher.  

Mathematics: A score in the range of 950–990 on the  Mathematics CRC Test or a Mathematics CRC Test score  below 950 and a Mathematics Diagnostic Test score of 6.

Your Reasoning scores a Proficient rating which is good.

Vitek1552 [10]2 years ago
6 0

Answer:

Explanation:

ur ELAR is 946 which is above the pass mark of 945

ur Math score of 932 is below the pass mark of 950

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Friction: a 50-kg box is resting on a horizontal floor. A force of 250 n directed at an angle of 30. 0° below the horizontal is
sergejj [24]

The net forces on the box parallel and perpendicular to the surface, respectively, are

∑ F[para] = (250 N) cos(-30.0°) - F[friction] = (50 kg) a

and

∑ F[perp] = F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

where a is the acceleration of the box. (We ultimately don't care what this acceleration is, though.)

To decide whether the friction here is static or kinetic, consider that when the box is at rest, the net force perpendicular to the floor is

∑ F[perp] = F[normal] - F[weight] = 0

so that, while at rest,

F[normal] = (50 kg) g = 490 N

Then with µ[s] = 0.40, the maximum magnitude of static friction would be

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The horizontal component of our pushing force is

(250 N) cos(-30.0°) ≈ 217 N

so the box will move in our case, and we will have kinetic friction with µ[k] = 0.30.

Solve the ∑ F[perp] = 0 equation for F[normal] :

F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

F[normal] - 125 N - 490 N = 0

F[normal] = 615 N

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2 years ago
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