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babunello [35]
3 years ago
11

Tools used to physically represent numbers​

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

The most frequently employed tools are traditional, which include physical ... These three tools can be used independently or conjointly, depending on the type of ... Learning tools can represent mathematical ideas in multiple ways, providing ... nature of concepts, such as numbers, thereby making them real and tangible,...

Step-by-step explanation:

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A merry-go-round has 25 horses. Each horse
iVinArrow [24]

Answer:

M

Step-by-step explanation:

337 / 25 = 13.48

Round to the nearest whole number = 13

The 13th letter of the alphabet is m, so:

The answer is M.

4 0
4 years ago
Amelie's bird cage is shaped like a rectangular prism. The cage has a height of 26 inches and a volume of 7,280 cubic inches. Am
jasenka [17]
The area of the news paper which fits in the bottom of the Amile's cage is 280 square inches because The area is said to be the product of the two sides ( length an breadth ) of the rectangle.
The volume is said to be the product of the length, breadth and height of the cage.
Here the height and volume are given in the square inches.
volume = L* B *H = 7280 Square inches whereas height is 26 inches.
AREA = L* B = by bringing the height in divide with volume we can obtain the L* B value which is said to be the value of the height .
4 0
3 years ago
A jar contains 3 oz of seed and is 1/6 full.<br><br> How much seed is in a full jar?
poizon [28]
X= number of ounces in the full jar
3 = 1/6 x
multiply both sides by 6:
18=x
18 oz.
3 0
4 years ago
How many 1 2/3 are in 1 1/6​
Flura [38]

Answer:

7/10

Step-by-step explanation:

To find how many of x are y, you solve <em>y/x</em>.

With our numbers, we have <em>7/6 ÷ 5/3</em>.

We can turn that into <em>7/6 × 3/5</em> = <em>21/30</em> = 7/10.

5 0
3 years ago
in the given figure, AB//PQ//CD. AB = x units. CD = y units and PQ = z unites. Prove that 1/x + 1/y = 1/z
Arlecino [84]
12. ∆ABD is similar to ∆PQD, so
   QD/z = BD/x
Likewise ∆CDB is similar to ∆PQB, so
   QB/z = BD/y

Since QD + QB = BD, you have
   QD/z + QB/z = BD/x + BD/y
   BD/z = BD/x + BD/y
Dividing by BD gives the desired result:
   1/x + 1/y = 1/z


13. Triangles ABD, BCD, and ACB are all similar. This means
   AB/AC = AD/AB
   AB² = AC×AD = (4 cm)×(9 cm)
   AB² = 36 cm²
   AB = 6 cm
and
   BD/CD = AD/BD
   BD² = CD×AD = (5 cm)×(4 cm)
   BD² = 20 cm²
   BD = 2√5 cm
7 0
3 years ago
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