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3 years ago

13

Solve 23y+1=16y+8. Check your solution. y= __

2 answers:

ra1l [238]3 years ago

4 0

Answer:

y=1

Step-by-step explanation:

23y+1=16y+8

minus 1 from both sides

23y=16y+7

minus 16y from both sides

7y=7

divide 7 from both sides

y=1

Checking Our Solution:

23(1)+1=16(1)+8

do all your multiplication first

23+1=16+8

add everything

24=24

and its all correct

OleMash [197]3 years ago

3 0

Hi bro,

7y=7

y=1

Okay??

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Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

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3 years ago

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PIT_PIT [208]

Answer:

p=4x^3−3x^2+5x−2/x

Step-by-step explanation:

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