What is the distance between points A and B?
1 answer:
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The images to solve this problem is in the attachment.
Answer: = 671.0 N;
= 300 N
Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:
=
and
=
Using trigonometry, shown in the second attachment, the values for each force are:
- Force of Static Friction
sin 20° =
=
. sin(20)
= 735.0.913
= 671.0
- Normal Force
cos 20° =
=
. cos (20)
= 735.0.408
= 300
The force of static friction is 671N and normal force is 300N
Answer:
Radius = 2.90 cm
Step-by-step explanation:
220 = 3.14 × {r}^{2} × 8.3
220 = 26.062 × {r}^{2}
220/26.062 = {r}^{2}
{r}^{2} = 8.44 ( approx )
r = √8.44
r = 2.90 cm. (approx)
Hope this helps .....
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