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3 years ago

What is the value of B and C

Mathematics

1 answer:

Margarita [4]3 years ago

5 0

Answer:

The value of b is 6 and the value of c is also 6

Step-by-step explanation:

We know that given triangles are congruent. When two triangles are congruent then their respective sides are also equal/congruent.

So,

ΔUWV≅ΔEDF

Then

WV ≅ DF

WU ≅ DE

UV ≅ EF

So,

Putting their respective value equal:

WV = DF

$9c = 10c-6\\10c-6 = 9c\\10c-6+6 = 9c+6\\10c = 9c+6\\10c-9c = 9c+6-9c\\c = 6\\and\\10b = b+54\\10b-b = b+54-b\\9b = 54\\\frac{9b}{9} = \frac{54}{9}\\b = 6$

Hence,

The value of b is 6 and the value of c is also 6

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Write an equation (in slope-intercept form) that is parallel to 4x + 5y = 10 and has the same y-intercept as -3x - 4y = 24.

mart [117]

Answer:

y = -4/5 x - 6

Step-by-step explanation:

First turn both standard form equations to slope-intercept form.

4x + 5y = 10 -3x - 4y = 24

-4x -4x +3x +3x

5y = -4x + 10 -4y = 3x + 24

5 5 -4 -4

y = -4/5 x + 2. y = -3/4 x - 6

Now that you have each in slope-intercept form, we can begin the magic.

So we know that this line's y-intercept will be -6.

Not to mention since it's parallel, that means it will share the same slope as y = -4/5 x + 2, which the slope is -4/5. All together it will be

y = -4/5 x - 6. Now we can graph the line's to see if we we're right. (Look at graphs, attached above⤴⤴⤴) As you can see they are parallel.

Hope this helped :)

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3 years ago

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sveta [45]

Answer: i think its 33%
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3 years ago

Jeremy rode his bicycle in a race. He averaged 15 mph and began the race 1 hour ahead of the other riders. The variable d repres

alekssr [168]

D = 15(t + 1)

Explanation:
It would be t + 1 rather than t - 1 because he has one *more* hour compared to the other riders.
The reason why t + 1 is in parentheses is because when solving, you'd have to first add instead of multiply.

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4 years ago

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Liono4ka [1.6K]

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4 years ago

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What is the solution to ln (x2 - 16) = 0?

bogdanovich [222]

ANSWER

$x = \pm \sqrt{17}$
EXPLANATION

The given equation is

$ln( {x}^{2} - 16) = 0$

Take antilogarithm of both sides to base e.

${e}^{ ln( {x}^{2} - 16) } = {e}^{0}$

This will simplify to

${x}^{2} - 16 = 1$

Group like terms to obtain,

${x}^{2} = 1 + 16$

${x}^{2} = 17$

Take square root of both sides to get,

$x = \pm \sqrt{17}$

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3 years ago

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