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1 answer:
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The angle of B is 56.2 degrees
<em><u>Solution:</u></em>
Given is a right angled triangle ABC
From given figure,
AB = 9
CB = 5
We have to find the angle of B
Let the angle of B be
By definition of cosine,
Here, adjacent = CB and hypotenuse = AB
Therefore,
Taking cos inverse on both sides,
Thus the angle of B is 56.22 degrees
Y = 3x + 1
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)