Find the axis of symmetry: Y=4x^2+16x-2

1 answer:

8 0

Do this by converting to vertex form

y = 4x^2 + 16x - 2

y = 4 (x^2 + 4x - 0.5) completing the square on x^2 + 4x:-

y = 4[(x + 2)^2 - 4.5]

the axis of symmetry is x = -2

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