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Rina8888 [55]
3 years ago
12

An equation is shown. 5.25 - 1.75 + c = 9.25 What value of c makes the equation true? *

Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0
B 5.75

Explaining:
5.25 - 1.75 = 3.5
3.5 - 9.25 = 5.75
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The original value of a Tv is $2300. As a new model of TVs become available, the value decreases by 2% each year. What will the
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2300*.02=46

46*7=322

2300+322=2622

2622
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3 years ago
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An automobile manufacturer claims that its van has a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contra
Yuliya22 [10]

Answer:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

p_v =2*P(z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is NOT significantly different from 31.3 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=31.1 represent the sample mean

\sigma=1.3 represent the population standard deviation for the sample  

n=140 sample size  

\mu_o =31.3 represent the value that we want to test  

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We can assume that we conduct a hypothesis in order to check if the true mean is equal to 31.3 , the system of hypothesis would be:  

Null hypothesis:\mu =31.3  

Alternative hypothesis:\mu \neq 31.3  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is NOT significantly different from 31.3 at 2% of signficance.  

5 0
3 years ago
Find the monthly interest payment in the situation described below. Assume that the monthly interest rate is 1 divided by 12 of
asambeis [7]

The monthly interest payment is 162

<h3>What is Interest?</h3>

Interest, in its most simple form, is calculated as a percent of the principal.

First,

monthly interest rate,

= 0.24/12

= 0.02.

Now,

Average monthly interest,

=0.02×$675

= $13.50.

Thus, the annual interest payments,

= 12×$13.50

= $162

Learn more about this concept here:

brainly.com/question/1435782

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3 0
2 years ago
The sales tax on a surfboard is $12. What is the percent of sales tax?
Svet_ta [14]
240 X .1 = 24;  24/2 = 12;  .1/2 = 0.05;  .05 X 100 = 5%
4 0
3 years ago
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The population of fish in a lake grew exponentially. In 2000, a researched estimated
cupoosta [38]

Answer:

a) P(t) = P₀ e⁰•⁰⁵⁴ᵗ

b) 2786 fishes

c) The estimated population will be 24000 in the year 2030.

Step-by-step explanation:

The function representing the population of fish in a lake as it grows exponentially

P(t) = P₀eᵏᵗ

If the base year is taken to be 2000

P₀ = 4780 fishes

k = constant

In 2010, P(t=10) = 8200 fishes, we can now solve for the constant

kt = k × 10 = 10k

8200 = 4780 e¹⁰ᵏ

e¹⁰ᵏ = (8200/4780) = 1.7155

In e¹⁰ᵏ = In 1.7155 = 0.5397

10k = 0.5397

k = 0.054 to 3 d.p

P(t) = P₀ e⁰•⁰⁵⁴ᵗ

b) What was the estimated population in 1990?

1990 is 10 years before 2000, hence, t = -10

P(t) = P₀ e⁰•⁰⁵⁴ᵗ

0.054t = 0.054 × -10 = -0.54

P₀ = 4780

P(t) = 4780 e⁻⁰•⁵⁴ = 4780 × 0.5829 = 2,786.4 = 2786 fishes to the nearest thousand

c) When will the population 24,000?

P(t) = 24000

P₀ = 4780

t = ?

24000 = 4780 e⁰•⁰⁵⁴ᵗ

e⁰•⁰⁵⁴ᵗ = (24000/4780) = 5.021

In e⁰•⁰⁵⁴ᵗ = In 5.021 = 1.6136

0.054t = 1.6136

t = (1.6136/0.054) = 29.88 years = 30 years to the nearest whole number.

Since the base year is 2000, 30 years after that is 2000 + 30 = 2030.

Hope this Helps!!!

8 0
3 years ago
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