All categories

3 years ago

Clarisse used the ordered pairs (0, 13) and (24, 5) for her trend line. What would be the y-intercept of her trend line?

Mathematics

1 answer:

laila [671]3 years ago

5 0

Answer:

Step-by-step explanation:

Remark

You have 2 points to solve the equation y = mx + b. After finding m, use either of the points to find b.

Formula

y = mx + b

m = (y2 - y1)/(x2 - x1)

Solution

y2 = 13
y1 = 5
x2 = 0
x1 = 24

m = (13 - 5)/(0 - 24)

m = 8 / - 24

m = - 1/3

y = mx + b

y = -1/3 x + b

Use (0,13) as the point.

13 = -1/3 * 0 + b

13 = b

The y intercept = (0,13)

You might be interested in

An artist mixes colors for a painting. She mixes 1.5 ounces of blue with 2.5 ounces of yellow to get the perfect shade of green.

lesya692 [45]

Answer:

4.5 ounces of yellow and 7.5 ounces of blue will create 12 ounces of the perfect shade of green.

Step-by-step explanation:

1.5 + 2.5 = 4 ounces.

Multiply by 3

4.5 + 7.5 = 12 ounces

So, she needs 4.5 ounces of yellow.

4 0

3 years ago

The points , (−15,1) and , (−7,r) lie on a line with slope 5/4. Find the missing coordinate r. Click image to enlarge

Nadya [2.5K]

The missing coordinate r is 11.

Solution:

Given points are (–15, 1) and (–7, r).

$x_{1}=-15, x_{2}=-7, y_{1}=1 \text { and } y_{2}=7$

Slope (m) = $\frac{5}{4}$

To find the missing coordinate r:

Slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute the given values in the formula.

$$\frac{5}{4}=\frac{r-1}{-7-(-15)}$

$$\frac{5}{4}=\frac{r-1}{-7+15}$

$$\frac{5}{4}=\frac{r-1}{8}$

Do cross multiplication.

$8 \times 5=4(r-1)$

40 = 4r – 4

Add 4 on both side of the equation.

44 = 4r

Divide by 4 on both side of the equation.

11 = r

⇒ r = 11

Hence the missing coordinate r is 11.

6 0

3 years ago

Brainliest and points!!

bezimeni [28]

Answer:

Step-by-step explanation:

1 x 5 = 5

5 x 5 = 25

25 x 5 = 125

125 x 5 = 625

and so on and so on

5 + 5 = 10 5 + 5 = 10

10 + 10 = 20

20 + 5 = 25

7 0

3 years ago

When solving the equation x2 – 8x - 7 = 0 by completing the square, which equation

IgorLugansk [536]

<h3>Answer:-</h3>

Lets Solve

$\\ \rm \longmapsto \: {x}^{2} - 8x - 7 = 0 \\ \\ \rm \longmapsto \: {x}^{2} - 8 {}^{}x = 7 \\ \\ \rm \longmapsto \: 4( {x}^{2} - 8x) = 4 \times 7 \\ \\ \rm \longmapsto \: {4x}^{2} - 32x = 28 \\ \\ \rm \longmapsto \: {(2x)}^{2} - 2 \times 2x \times 8 = 28 \\ \\ \rm \longmapsto \: (2x) {}^{2} - 2 \times 2x \times 8 + {8}^{2} = 28 + {8}^{2} \\ \\ \rm \longmapsto \: {(2x - 8)}^{2} = 64 + 28 \\ \\ \rm \longmapsto \: {(2x - 8)}^{2} = 92 \\ \\ \rm \longmapsto \: 2x - 8 = \underline{ + }9.3 \\ \\ \rm \longmapsto \:2x = 8 + 9.3 \: or \: 8 - 9.3 \\ \\ \rm \longmapsto \:2x = 17.3 \:or \: - 1.3 \\ \\ \rm \longmapsto \:2x = 17.3 \\ \\ \rm \longmapsto \:x = \frac{17.3}{2} \\ \\ \rm \longmapsto x = \:8.6$

Ignore negative value

4 0

3 years ago

Doing math watch and have no idea what to do

photoshop1234 [79]

Answer:

A=πr^2

=3.142×11.2^2

=3.142×125.44

=394.13cm^2

7 0

3 years ago