1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
faltersainse [42]
3 years ago
15

A classroom had 8 rows of desks with 6 desks in each row. Four desks were removed from the room. How many desks were left?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0
Answer: 44 desks.

First of all, you need to find how many desks there are in total. To find it, you need to multiply 8 with 6.

8 x 6 = 48

Next, it says that four desks were removed. All you need to do is subtract 4 from 48.

48 - 4 = 44.
You might be interested in
Is 7/8 equivalent to 3/4?
fredd [130]
No, 3/4 is equivalent to 6/8 and 7/8 is in its final form
8 0
3 years ago
Help please uh yes please
Ivan

Answer:

D

Step-by-step explanation:

4 1/2, square root of 24, 5, 5.1

4 0
3 years ago
Read 2 more answers
Solve for X. *<br> (1 Point)<br> x + 70<br> 76°<br> 410
Yuki888 [10]

Answer:

x = -7

Step-by-step explanation:

41 + 76 + x + 70 = 180

x + 187 = 180

x = 180 - 187

x = -7

7 0
2 years ago
Read 2 more answers
What is the volume of a cylinder with a height of 16.5 in and a base with a diameter of 17.2 in, to the nearest tenth of a cubic
LenKa [72]
V=S(base)*h=pi*r2
V=pi*r2*h
V=3,14*(half of diameter in square)8,75in square*16,5
V=3,14*8,75(in square)*16,5in
===3966,7
This is correct!!!Im pretty sure!!!☺️
3 0
3 years ago
Read 2 more answers
What is the probability that a five-card poker hand contains exactly one ace?.
spin [16.1K]

The probability of selecting exactly one ace is its likelihood

The probability that a five-card poker hand contains exactly one ace is 29.95%

<h3>How to determine the probability?</h3>

There are 4 aces in a standard deck of 52 cards.

The probability of selecting an ace would be:

p = 4/52

Also, there are 48 non-ace cards in the standard deck

So, the probability of selecting a non-ace after an ace has been selected is:

p = 48/51

The probability of selecting a non-ace up to the fifth selection are:

  • After two cards have been selected is:  47/50.
  • After three cards have been selected is:  46/49.
  • After four cards have been selected is:  45/48.

The required probability is then calculated as:

P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Where n is the number of cards i.e. 5

So, we have:

P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Evaluate

P(1 Ace) = 0.2995

Express as percentage

P(1 Ace) = 29.95%

Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%

Read more about probability at:

brainly.com/question/25870256

8 0
3 years ago
Other questions:
  • PLEASE HELP WITH MATH . REALLY APPRECIATED . EASY 9 <br> POINTS .
    12·2 answers
  • Which step will translatef(x)=3^xto g(x)=3^x+1 +4
    13·1 answer
  • PLZ HELP ME!!!!!!!!!
    15·1 answer
  • After Jessie gave $20 to his brother,<br> he had $33 left. How much did Jessie<br> have originally?
    7·1 answer
  • In the data set below, what is the mode?<br> 15, 21, 26, 25, 21, 23, 28, 21, 25, 23
    14·1 answer
  • 27-12+4. Please read description.
    15·2 answers
  • This diagram shows a right square pyramid and some of its dimensions. What is the volume of the pyramid?
    5·1 answer
  • Find what value of x makes the equation true
    13·1 answer
  • What is the best way to solve a literal equation?
    12·1 answer
  • What is the difference between dividing fractions less than 1 and dividing mixed numbers
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!