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DedPeter [7]
2 years ago
5

Aaron, Bonny and Connor are playing a game with cards.

Mathematics
1 answer:
professor190 [17]2 years ago
6 0

Let the number of cards Aaron has : A

Given :

⊕   Bonny has twice as many cards as Aaron

⊕   Connor has 6 cards more than Bonny

⊕   Total cards : 101

⇒  Number of cards Bonny has : 2A

⇒  Number of cards Connor has : 2A + 6

⇒   Aaron cards + Bonny cards + Connor cards = 101

⇒   A + 2A + 2A + 6 = 101

⇒   5A = 101 - 6

⇒   5A = 95

⇒   A = 19

<u>Answer</u> : Aaron has 19 Cards

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Find the slope of the line passing through the points (-8,-8) and (2,-8)
san4es73 [151]

Answer:

The slope is -8 :)

Step-by-step explanation:

trust me

4 0
2 years ago
[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6
viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

              (b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

                  Height (in inches) of a 25 year old man is a normal random variable with mean g=71 and variance o^{2} =6.25.

To find:  (a) What percentage of 25 year old men are 6 feet, 2 inches tall

               (b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>74in]

                           P[X>74] = P[\frac{X-g}{o} > \frac{74-71}{2.5}]

                                         = P[Z > 1.2]

                                         = 1 - P[Z ≤ 1.2]

                                         = 1 - Ф (1.2)

                                         = 1 - 0.8849

                                         = 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, 6ft 5in - X, 6ft]

     P[X > 6ft 5in I X > 6ft] = P[X > 77 I X > 72]

                                          = \frac{P[X > 77]}{P[ X > 72]}

                                          = \frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}]  }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }

                                          = \frac{P[Z >2.4]}{P[Z>0.4]}

                                          =  \frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }

                                          = \frac{1-0.9918}{1-0.6554}

                                          = \frac{0.0082}{0.3446}

                                          = 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0
3 years ago
Timothy runs on a treadmill at an average speed of 5 meters per second. How many minutes does it take Timothy to run 2.4 kilomet
ruslelena [56]
It will take 8 minutes.
You use a proportion 
5/1=2400/x you use 2400 because 2.4km=2400 meters and u need to use the same unit of measurement.
so cross multiplying gives you 5x=2400 which is equal to 480. BUT this is 48 seconds, and it asks you how many minutes, not seconds. So, you divide by 60 because there are 6 seconds in a minute, and you get 8.
6 0
2 years ago
A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. The mean is found to be 10.3
user100 [1]

Answer:

Confidence interval for the true mean number of reproductions per hour for the bacteria is (10.1,10.5).

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 10.3

Population standard deviation, σ = 2.1

Sample size, n = 728

Alpha, α = 0.01

Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58

10.3 \pm 2.58(\frac{2.1}{\sqrt{728}} ) = 10.3 \pm 0.2008 = (10.0992,10.5008) \approx (10.1,10.5)

6 0
2 years ago
The ratio of the volumes of two similar solid polyhedra is equal to the square of the ratio between their edges.
Leto [7]
False hope it’s right
4 0
3 years ago
Read 2 more answers
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