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natka813 [3]
3 years ago
8

Find the mean, median, and mode of the following set of data:

Mathematics
2 answers:
viva [34]3 years ago
8 0
Mean: 49.6
Median: 52
Mode: 54

For the median, we have to put the data in order:

37, 42, 48, 51, 52, 53, 54, 54, 55.

The middle number is the median: 52 (there are 4 numbers higher and 4 numbers lower than 52)

The mode is the number that occurs most often. 54 is the only one that shows up more than once.

To get the money, we add all the numbers, which = 446. Then divide that by how many numbers there are (9)
446/9 = 49.555555 = 49.6
ddd [48]3 years ago
7 0

Answer:

Step-by-step explanation:

mode is means the data which is repeated maximum number of times.

here 54 is repeated maximum number of times so the mode of the given data is 54.

to calculate median u must arrange the data from ascending to descending order.

37 , 42 , 48 , 51 , 52 , 53 , 54 , 54 , 55 ,

median = (N + 1) /2    (N means number of data)

=9 + 1/2

=10/2

=5 th term

=52

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A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

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Answer:

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