Let x = number of months.
Let y = total number of fish in pond.
6% of 3,000 = 180 fish
We can use an equation to help us with this problem.
y = 3,000 + 180x - 400x. Combine like terms.
y = 3,000 - 220x. Plug 9 in for x.
y = 3,000 - 220(9). Solve for y
y = 1,020.
There are 1,020 fish in the pond after 9 months.
Answer:
Step-by-step explanation:
When x =3 y=-1
X =2 y =0
X=0 y =3
X = -1 y=6
So c g d f true
For when x=2, You get 14.
For when x=3, You get 11.
Therefore, x=2 gives a bigger value.
17 + y (?) .................................................
Answer:
3n -6
Step-by-step explanation:
Let the number be n :
Product of 3 and n = 3n
6 less will be 3n- 6
Hope this helped and have a good day
