Answer:
You can't really say it matters whether it's short or long
Explanation:
There several coding language some short and some long with different purposes so it doesn't really make a difference
Although some coders have been able to shorten some codes so I'd say shorter is faster and be[er and easier to memorize
Thanks hope I was helpful
Answer:
Customer(1) - (1) Vehicle.
Explanation:
Cardinality is the mapping of entities or group of entities to a cardinal value. It tries to show the relationship between two objects like a cups in a shelf or plates in racks.
The car dealer in the question, sells one car to a customer and keep or prioritise the record of the main owner of the acquired vehicle. So the maximum cardinality assignment of the customer and vehicle is one (1) to one (1) mapping.
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
You have to destroy the hard drive as it is like a memory for the computer so it can never be deleted
It loses power and most likely stops working
