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Rus_ich [418]
3 years ago
12

Solve the equation -6a(-5-2a)=0

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

A=0,-2 1/2

Step-by-step explanation:

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What is the answer -6x•-89-45g
Dennis_Churaev [7]
Factored
-3(-178x+15g)

Simplified
534x-45g
4 0
3 years ago
- How many solutions does the system of equations shown below have?
vfiekz [6]
It’s D. Hope this helps
3 0
2 years ago
What is the surface area of a cylinder whose base radius is 7 cm and whose height is 8 cm?
Mnenie [13.5K]

Answer:

659.73

Step-by-step explanation:

i searched up surface area cylinder calculator to get the answer but incase u can't use that

A= 2(pi) r h + 2 (pi) r ^2

in this case it would be

A= 2 (pi) (7) (8) + 2(pi) 7^2

after that u should be able to get 659.73

if u didnt understand the explanation try searching up "surface area cylinder calculator" and it should pop up!

(my fault if the answer is wrong btw)

6 0
3 years ago
PLEASE HELP ME ASAP! Giving brainliest<br> SHOW YOUR WORK FOR BOTH QUESTIONS
EleoNora [17]

Answer:

The Proof for question no 20 and 21 are below.

Step-by-step explanation:

20.

Given:

∠PTR≅∠RSP

PT ≅ RS

To Prove:

ΔPQT ≅ ΔRQS

Proof:

In ΔPQT and ΔRQS

Statements                    Reasons

1. ∠PTR ≅ ∠RSP       1 .Given

2. ∠PQT ≅ ∠ROS     2. Vertical Opposite Angle Theorem.

3. PT ≅ RS                3. Given

4. ΔPQT ≅ ΔRQS     4. By A-A-S Congruence Postulate ....Proved

21.

Given:

PO ≅ SO

O is the Mid Point of NT

To Prove:

∠N ≅ ∠T

Proof:

In ΔPON and ΔSOT

Statements                    Reasons

1. PO ≅ S O              1 .Given

2. ∠PON ≅ ∠SOT    2. Vertical Opposite Angle Theorem.

3. NO ≅ TO              3. O is the Mid Point of NT

4. ΔPON ≅ ΔSOT    4. By S-A-S Congruence Postulate

5. ∠N ≅ ∠T               5. Corresponding Parts of Congruent Triangles are Congruent .( CPCTC )...Proved

3 0
3 years ago
EB and DA are diameters of circle Y. What is the measure of arc EDC?
Dmitrij [34]

Answer:

Option (D). 110°

Step-by-step explanation:

Since EB and AD are diameter,

m(\widehat{ECB}) = m(\widehat{ACD}) = 180°

m(\widehat{ECB})=m(\widehat{EDC})+m(\widehat{BC}) = 180° -------(1)

And m(\widehat{ACD})=m(\widehat{AB})+m(\widehat{BCD})

180° = 40° + m(\widehat{BCD})

m(\widehat{BCD}) = 140°

Since, m(\widehat{BCD})=m(\widehat{BC})+m(\widehat{CD})

2m(\widehat{BC}) = 140° [Given m(\widehat{BC})=m(\widehat{CD})]

m(\widehat{BC}) = 70°

From equation (1),

m(\widehat{EDC}}) = 180° - m(\widehat{BC})

m(\widehat{EDC}}) = 180°- 70°

Therefore, measure of arc(EDC) = 110°

Option (D) will be the answer.

4 0
3 years ago
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