Let's see what we can fill in here.
<ACE = 130
180 - 50 = 130
Now that we have two sides and an included angle, we can use the Law of Cosines.
Law of Cosines: c^2 = a^2 + b^2 - 2ab(cos(C))
Let's plug in what we know and solve!
c^2 = 40^2 + 38^2 - 2(40)(38)(cos(130))
R = 70.69706
Hope this helps!! :)
BLUF: ANS=4.0 ft^2
Arch = Rect - (Sector - Triangle)
rect = 5.7*1.5
Sector = pi r^2 /4
= 4pi
triangle = BH /2
=

Step-by-step explanation: