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3 years ago

For which equation is s = 9 not the solution?

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

Answer:

what is the equations?

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The Three sides of a triangle are, n, 4n-2, 4n-7. if the perimeter of the traingle is 45cm, what is the length of each side?

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Step-by-step explanation:

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4 years ago

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A=1/2w(b+c) solve for c

kaheart [24]

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Answer:

c = 2A/w -b

Step-by-step explanation:

Multiply by the inverse of the coefficient of the parentheses.

$A=\dfrac{w}{2}(b+c)\\\\\dfrac{2A}{w}=b+c\\\\\boxed{c=\dfrac{2A}{w}-b} \qquad\text{subtract $b$}$

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3 years ago

Please help me with this question

malfutka [58]

2/9

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8. A dolphin is traveling 5.5 meters

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Distance = final height - depthOFdolphin
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3 years ago

Evaluate cosA/2 given cosA=-1/3 and tanA >0

mote1985 [20]

Answer:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

Step-by-step explanation:

Given that:

$cosA=-\dfrac{1}3$

and

$tanA > 0$

To find:

$cos\dfrac{A}{2} = ?$

Solution:

First of all,we have cos value as negative and tan value as positive.

It is possible in the 3rd quadrant only.

$\dfrac{A}{2}$ will lie in the 2nd quadrant so $cos\dfrac{A}{2}$ will be negative again.

Because Cosine is positive in 1st and 4th quadrant.

Formula:

$cos2\theta =2cos^2(\theta) - 1$

Here $\theta = \frac{A}{2}$

$cosA =2cos^2(\dfrac{A}{2}) - 1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =cosA+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =-\dfrac{1}3+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =\dfrac{2}3\\\Rightarrow cos(\dfrac{A}{2}) = \pm \dfrac{1}{\sqrt3}$

But as we have discussed, $cos\dfrac{A}{2}$ will be negative.

So, answer is:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

7 0

3 years ago