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Mashutka [201]
3 years ago
5

(2x - 1) (5x + 3) - (2x - 1)(x - 1)​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

{8x}^{2}  + 4x - 4

Step-by-step explanation:

1) Use foil method: (a + b ) (c + d) = ac + ad + bc + bd.

{10x}^{2}+6x-5x-3-(2x-1)(x - 1)

2) Use foil method: (a + b ) (c + d) = ac + ad + bc + bd.

{10x}^{2}  + 6x - 5x - 3 - ( {2x}^{2}  - 2x - x + 1

3) Remove parentheses.

{10x}^{2}  + 6x - 5x - 3 -  {2x}^{2}  - 2x - x  + 1

4) Collect like terms.

( {10x}^{2}  -  {2x}^{2} ) + (6x - 5x + 2x + x) + ( - 3 - 1)

5) Simplify.

{8x}^{2}  + 4x - 4

<u><em>Therefor</em><em>,</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em></u><em><u> </u></em><em><u>8x</u></em><em><u>²</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>4x</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>4</u></em><em><u>.</u></em>

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Find a122 of the sequence 5, 8, 11
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5, 8, 11, ... is an arithmetic sequence where:

a_1=5;\ a_2=8;\ d=8-5=3\\\\a_n=a_1+(n-1)d\to a_n=5+(n-1)\cdot3=5+3n-3=2+3n\\\\therefore\\\\a_{122}=2+3\cdot122=2+366=368
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Simplify the expression 6C5.<br> a.6.<br> b. 24<br> C. 30<br> d. 720
Lana71 [14]
<h3>Answer:  A) 6</h3>

=====================================================

Explanation:

Plug n = 6 and r = 5 into the nCr combination formula

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_6 C _5 = \frac{6!}{5!*(6-5)!}\\\\_6 C _5 = \frac{6!}{5!*1!}\\\\_6 C _5 = \frac{6*5*4*3*2*1}{5*4*3*2*1*1}\\\\_6 C _5 = \frac{720}{120}\\\\_6 C _5 = 6\\\\

Or you could use the shortcut

_n C _{n-1} = n\\\\

Yet another path you could take is to use Pascal's Triangle. Locate the row that starts with 1,6,... and then locate the second to last item. That value in the triangle is 6.

A real world interpretation is to consider having 6 people and you are selecting 5 of them to form a group where order doesn't matter. How many ways are there to do this? Well there are 6 such ways because there are 6 ways to leave someone out of the group.

8 0
2 years ago
Question:
aleksklad [387]

Answer:

There are 10 blocks in a row (section). There are  6 rows (sections).

1.

A. If each block has a value of one, what is the value for a section of blocks?

<h2> 10</h2>

There are 10 blocks in a section. 10 * 1 = 10

B. What is the total value of all the blocks, write an equation?

<h2>60</h2>

There are 6 sections. There are 10 blocks in a section. 6 * 10 * 1 = 60

2.

A. If each block has a value of ten, what is the value for a section of blocks?

<h2>  100</h2>

There are 10 blocks in a section. 10 * 10 = 100

B. What is the total value of all the blocks, write an equation?

<h2>600</h2>

There are 6 sections. There are 10 blocks in a section. 60 * 10 * 10 = 600

4 0
3 years ago
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