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3 years ago

MY LAST QUESTION PLEASE HELP

Mathematics

1 answer:

liraira [26]3 years ago

3 0

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj / hyp

cos 60 = 6/hyp

hyp = 6 / cos 60

hyp = 6 / (1/2)

htp = 12

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Ayudemen en este tema porfavor. <br> 16x²—4x=0

Lelechka [254]

Answer:

x=0, 1/4

Step-by-step explanation:

16x^2-4x=0

factor out the 4x,

4x(4x-1)=0

zero property,

4x=0, 4x-1=0,

x=0/4=0

4x=0+1

4x=1

x=1/4

6 0

3 years ago

A physical education teacher plans to divide the seventh graders at Wilson middle school into teams of equal size for a year-end

serg [7]

Answer:

• It is possible to divide the seventh graders into teams of equal sizes.

• 13 students should be on each team.

Explanation:

The seventh grade of Wilson consists of three classes; one with 28 students, one with 29, and one with 34. Therefore, the total number of students in seventh grade is:

$\text{Total}=28+29+34=91$

He wants each team to have between 4 and 8 students.

$\begin{gathered} \frac{91}{4}\approx22.75 \\ \frac{91}{5}\approx18.2 \\ \frac{91}{6}\approx15.2 \\ \frac{91}{7}\approx13 \\ \frac{91}{8}\approx11.4 \end{gathered}$

Therefore:

• It is possible to divide the seventh graders into teams of equal sizes.

• 13 students should be on each team.

8 0

1 year ago

True or false: sometimes, a quadratic expression cannot be factored.

lyudmila [28]

Answer:

true

Step-by-step explanation:

8 0

3 years ago

Solve 5x = 10x - 5(2x-3) for x. Show your work.

diamong [38]

Eliminate parentheses using the distributive property.

... 5x = 10x -10x +15

Collect terms, then divide by the coefficient of x.

... 5x = 15

... x = 3

5 0

3 years ago

Exponential and growth. Pls help me T^T

sergiy2304 [10]

Answer: r = -0.14

<u>Step-by-step explanation:</u>

$K=K_o\cdot e^{rn}\quad \text{where;}\\\bullet K\ \text{is the final amount of Kristinite}\\\bullet K_o\ \text{is the initial amount of Kristinite}\\\bullet r\ \text{is the rate of decay}\\\bullet n\ \text{is the number of seconds the decay has occurred}\\\\\\\text{Given:}\\\\K: \dfrac{1}{2}K_o\\\\r: unknown\\\\n: 2\\\\\\K=K_o\cdot e^{rn}\\\\\\\dfrac{1}{2}K_o=K_o\cdot e^{r(5)}\\\\\\\dfrac{1}{2}=e^{5r}\\\\\\ln\dfrac{1}{2}=5r\\\\\\\dfrac{ln\dfrac{1}{2}}{5}=r\\\\\\-0.14=r\\$

8 0

3 years ago