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Answer:
Equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1 is
Step-by-step explanation:
We need to write equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1
The equation will be in slope-intercept form i.e where m is slope and b is y-intercept.
Finding Slope
Since the lines are parallel to each other, their slopes will be equal.
Slope of given line: y = 3x + 1 is 3 (Compare it with general equation we get m = 3)
So, slope of required line is: m=3
Finding y-intercept
Using the point (6,-3) and slope m = 3 we can find y-intercept by using the formula:
So, we get y-intercept: b= -21
Equation of required line
The equation of required line having slope m=3 and y-intercept b = -21 is:
So, equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1 is