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SVEN [57.7K]
3 years ago
5

How is the counting principle mathematically used?

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0

Answer: multiplying outcomes

Step-by-step explanation:

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A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard dev
Luden [163]

Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:


z (109.1) = (X-mean)/standard dev

= 109.1 – 108/ 0.6

= 1.1/0.6

=1.83333, look this up in the z table.


P(x < 109.1) = P(z < 1.8333) = 0.97 or 97%

3 0
3 years ago
If the number is divisible both 3 and 4, find the greatest common fact
madam [21]
12 | 3*4=12 therefor any number that is divisible by 3 and 4 is also divisible by 12
8 0
3 years ago
You deposit $500 in a savings account that earns 2.5% interest compounded yearly. Find the balance in the account after 1 year.
Viktor [21]

Answer:

$512.5

Step-by-step explanation:

Given data

P= $500

R=2.5%

T= 1 year

The compound interest formula is

A=P(1+r)^t

substitute

A=500(1+0.025)^1

A=500(1.025)

A=500*1.025

A=$512.5

Hence the balance is $512.5

4 0
3 years ago
Hi need help for this maths question
Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}

c) The mean is given by the integral,

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy

Integrate by parts, with

u = y \implies du = dy

dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}

Then

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)

\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy

\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}

8 0
2 years ago
If a van traveled 240 miles in 4 hours, how far could the van travel in 5 hours?
Mandarinka [93]

Answer: i think 300

Step-by-step explanation: i divided 240 by 4 and got 60 then multiplied 60X5=300

7 0
3 years ago
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