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Alika [10]
3 years ago
8

The value of a stock increases by 8% each year.

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Answer:

if it increases 8% each year, the next year it's not 8% of the original, but 8% of the 108% and so forth.

The increase after 10 years is (108%)^10 - 100% which is bigger than 80%.

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Identify the slope in y=-1/3x + 2<br><br> Hint: y = mx + b<br> 1. -1/3<br> 2. 2<br> 3. -2/3<br> 4. 1
scZoUnD [109]

Answer:

A) -1/3

Step-by-step explanation:

y = mx + b

    m = slope

    b = y-intercept

y = -1/3x + 2

    m = -1/3

3 0
3 years ago
Determine whether the lines below are parallel, perpendicular, or neither. *<br> y=2x+9<br> x-2y=-6
Luba_88 [7]

Answer:

perpendicular

Step-by-step explanation:

because m1×m2=-1

6 0
3 years ago
Which statement describes the domain of the function f(x)=3x/4x(x)-4
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3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
4 years ago
A gain of five meters​
Stella [2.4K]

1.A gain of five meters:5

Because gain=+

3 0
3 years ago
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