Question

Y= abx that goes through points (0,13) and (2,325)

Answer 1

Answer:

$y = 13(5)^x$

Step-by-step explanation:

We are given the following exponential function:

$y = ab^x$

(0,13)

This means that when $x = 0, y = 13$. So

$y = ab^x$

$13 = ab^0$

$a = 13$

Then

$y = 13b^x$

(2,325)

This means that when $x = 2, y = 325$ We use this to find b. So

$y = 13b^x$

$13b^2 = 325$

$b^2 = \frac{325}{13}$

$b^2 = 25$

$b = 5$

Thus

$y = 13(5)^x$