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3 years ago

Please help! I’ll do anything I’ll give u brainly!

Mathematics

1 answer:

AnnyKZ [126]3 years ago

7 0

For the first part I know it’s either c or d, and I’m pretty sure it’s d. For the second part you have to graph the equation y > -2x + 3. Make sure when you graph your line is dotted and you shade all of the graph that is above the line.

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3 years ago

A circle is centered at the point (-7, -1) and passes through the point (8, 7).The radius of the circle is____ units. The point

denis-greek [22]

Answer:

Part 1) The radius of the circle is r=17 units

Part 2) The points (-15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(-7, -1) and (8, 7)

substitute

$r=\sqrt{(7+1)^{2}+(8+7)^{2}}$

$r=\sqrt{(8)^{2}+(15)^{2}}$

$r=\sqrt{289}$

$r=17\ units$

step 2

Find out the y-coordinate of point (-15,y)

The equation of the circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute the values

$(x+7)^2+(y+1)^2=17^2$

$(x+7)^2+(y+1)^2=289$

Substitute the value of x=-15 in the equation

$(-15+7)^2+(y+1)^2=289$

$64+(y+1)^2=289$

$(y+1)^2=289-64$

$(y+1)^2=225$

square root both sides

$(y+1)=(+/-)15$

$y=-1(+/-)15$

$y=-1(+)15=14$

$y=-1(-)15=-16$

therefore

we have two solutions

point (-15,14) and point (-15,-16)

see the attached figure to better understand the problem

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