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Crazy boy [7]
3 years ago
5

Question 13. Please

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0

Answer:

d

Step-by-step explanation:

Δ OPG is right with hypotenuse OG being the radius of the circle

Using Pythagoras' identity in the right triangle

OG² = OP² + PG²

[ PG = 11 , since OP is the perpendicular bisector of FG ]

OG² = 8² + 11² = 64 + 121 = 185

Δ OQS is right with hypotenuse OS being the radius

Using Pythagoras' identity

OS² = QS² + OQ² , that is

185 = 13² + x²

185 = 169 + x² ( subtract 169 from both sides )

16 = x² ( take the square root of both sides )

4 = x → d

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|a+bi| = √(a² + b²)

-4-√2 i -> take a = -4 and b = -√2

|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
               = </span><span>√[ 16 + 2<span> ]
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the absolute value is 3√2</span>

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brainly.com/question/1015291

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