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Inessa05 [86]
3 years ago
12

Which type of function is shown in the table below.

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

it is a not a function

Step-by-step explanation:

if you times 51 that's a hundred

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2. In a relationship between variables, what is the variable called that changes in response to
valkas [14]

Answer:

A dependent variable

Step-by-step explanation:

is a variable whose value will change depending on the value of another variable, called the independent variable. Dependent variables are also known as outcome variables, left-hand-side variables, or response variables.

4 0
3 years ago
Which of the following is a solution to tan^2 x-1=0? a.45 degrees, b.120 degrees, c.240 degrees, d.330 degrees
andrew-mc [135]
Do you want a general solution or from 0 <= x < 2pi?

tan^2(2x) - 1 = 0
tan^2(2x) = 1

Take the square root of both sides,

tan(2x) = +/- 1

Two equations:
tan(2x) = 1
tan(2x) = -1

Solve each equation.

tan(2x) = 1, 2x = {pi/4, 5pi/4, 9pi/4, 13pi/4},
x = { pi/8, 5pi/8, 9pi/8, 13pi/8 }

tan(2x) = -1, 2x = { 3pi/4, 7pi/4, 11pi/4, 15pi/4 },
x = { 3pi/8, 7pi/8, 11pi/8, 15pi/8}

So for solutions within [0, 2pi),

x = {pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8 }
6 0
3 years ago
Hey everyone, could someone please help me with my math exam? It is Algebra 1. Please help!
Rus_ich [418]

here is my answer. i beleive i answered all of them. but i answered all i know hope it helps!

Download docx
3 0
3 years ago
Write 2 equivalent expressions that illustrate the associative property of addition
Katen [24]
(5 + 2) + 1 = 5 + (2 + 1)
6 0
4 years ago
write the equation of the line that passes through the point (-1,-6) and is perpendicular to a line that passes through the poin
Burka [1]

Answer:

y=\frac{2}{3}x-\frac{16}{3}

Step-by-step explanation:

step 1

Find the slope of the given line

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(-2,5) and (-4,8)

substitute the values in the formula

m=\frac{8-5}{-4+2}

m=\frac{3}{-2}

m=-\frac{3}{2}

step 2

Find the slope of the perpendicular line to the given line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

so

m_1*m_2=-1

m_1=-\frac{3}{2} ----> slope of the given line

therefore

m_2=\frac{2}{3} ---> slope of the perpendicular line to the given line

step 2

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{3}

point\ (-1,-6)

substitute

y+6=\frac{2}{3}(x+1)

step 3

Convert to slope intercept form

y=mx+b

isolate the variable y

y+6=\frac{2}{3}x+\frac{2}{3}

y=\frac{2}{3}x+\frac{2}{3}-6

y=\frac{2}{3}x-\frac{16}{3}

4 0
4 years ago
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