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3 years ago

Which situation can be modeled by the equation 705 – m= 430? help !!!!

2 answers:

nataly862011 [7]3 years ago

8 0

Answer: Luigi has 705 wine kegs at his winery, and he delivers (m) amount of them to his brother at the marketplace. How many did he deliver in order to have 430 left?

I hope this helped!

777dan777 [17]3 years ago

6 0

Real world example could be:
Consider x is time in minutes
Consider y is the amount of fish food required in grams

The equation could then represent how much food (in grams) that a fish needs to be fed x minutes after it was previously fed.

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What is the value of (-7 +31) - (2-61)?

forsale [732]

Answer: 83

Step-by-step explanation:

(-7+31) - (2-61)

(24) - 2+61

22+61

7 0

3 years ago

Helppppppppppppppppppppppppppppp what is 8/0

ad-work [718]

Answer:

8/10 is .8

Step-by-step explanation:

You divide 8 by 10.

4 0

4 years ago

Read 2 more answers

Hello please help me on these questions!

Tatiana [17]

1.) 1.19
2.) 0.27
3.) 0.41
4.) 0.92
5.)0.13

Please make me as brainlyest answer, 5 starts, a thank you, and Comment!

5 0

3 years ago

Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This

Alik [6]

Answer:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

$\hat p=\frac{19}{50}=0.38$ estimated proportion of businesses were highly profitable

$p_o=0.28$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:

Null hypothesis: $p=0.28$

Alternative hypothesis: $p \neq 0.28$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>1.575)=0.115$

4 0

4 years ago

What is the equation of the line that passes through the point (-4, 2) and has a slope of -5/4?

gulaghasi [49]

Answer:

y = -5/4 x - 3 is the slope-intercept form

5x + 4y = -12 is the standard form

Step-by-step explanation:

Use the point-slope form: $y - y_{1} = m(x - x_{1})$

$(x_{1}, y_{1})$ = (-4, 2)

y - 2 = -5/4(x + 4) Multiply by 4 to remove the fraction

4y - 8 = -5(x + 4)

4y - 8 = -5x - 20

4y = -5x - 12

y = -5/4 x - 3 is the slope-intercept form

5x + 4y = -12 is the standard form

6 0

3 years ago