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3 years ago

Find a formula for a geometric sequence that begins with 11, -33, 99

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

Step-by-step explanation:

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How to solve 2/3x+15=17 please explain to me how to solve this.

Natasha2012 [34]

2/3 x + 15 = 17
2/3 x = 17 - 15
2/3 x = 2
x = 2 / (2/3)
2/1 * 3/2 = 6/2 = 3
x = 3

5 0

4 years ago

Read 2 more answers

What is the measure of angle R?

Alika [10]

Answer:

m<R = 22.62°

Step-by-step explanation:

Reference angle = R

Opposite = 5 cm

Hypotenuse = 13 cm

Apply the trigonometric function SOH:

Sin R = Opp/Hyp

$Sin (R) = \frac{5}{13}$

$R = sin^{-1}(\frac{5}{13})$

R = 22.6198649°

m<R = 22.62° (nearest hundredth)

3 0

3 years ago

What is the complete factorization of the polynomial below?

aksik [14]

Option A: $(x+1)(x+3 i)(x-3 i)$ is the complete factorization of the polynomial $x^{3} +x^{2} +9x+9$

Explanation:

The polynomial is $x^{3} +x^{2} +9x+9$

Now, we shall find the complete factorization of the polynomial.

Let us group the common terms, we have,

$\left(x^{3}+x^{2}\right)+(9 x+9)$

Taking out the common terms,

$x^{2} (x+1)+9(x+1)$

Factor out $x+1$ from both the terms, we have,

$\left(x^{2}+9\right)(x+1)=0$

The term $\left(x^{2}+9)\right.$ can be factored as

$\begin{aligned}x^{2}+9 &=0 \\x^{2} &=-9 \\x &=\pm 3 i\end{aligned}$ and $\begin{aligned}x+1 &=0 \\x &=-1\end{aligned}$

Thus, the roots are $x=\pm 3 i$ and $x=-1$

These roots can be written as $(x+1)(x+3 i)(x-3 i)$

Thus, the complete factorization of the polynomial is $(x+1)(x+3 i)(x-3 i)$

8 0

3 years ago

Read 2 more answers

Mr brown shares with the class that 70 percent of the students got an a on the English quiz if Mr brown has 100 student what per

Kay [80]

The other 30 percent of the class

8 0

2 years ago

Line m has a slope of 8/5. line n is perpendicular to line m. what is the slope of line n?

yulyashka [42]

$m_{1}m_{2} = - 1$

$\frac{8}{5} \times m_{2} = - 1$

$m_{2} = \frac{5}{8} \times - 1$

$\boxed{ m_{2} = \frac{ - 5}{8} }$

4 0

2 years ago