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3 years ago

Write a c++ program to print even numbers from 1 to 20

Computers and Technology

1 answer:

Novay_Z [31]3 years ago

8 0

Answer:

#include <bits/stdc++.h>

using namespace std;

// Function to print even numbers

void printEvenNumbers(int N)

{

cout << "Even: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are divisible by 2

if (i % 2 == 0)

cout << i << " ";

}

// Function to print odd numbers

void printOddNumbers(int N)

{

cout << "\nOdd: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are not divisible by 2

if (i % 2 != 0)

cout << i << " ";

}

// Driver code

int main()

{

int N = 20;

printEvenNumbers(N);

printOddNumbers(N);

return 0;

}

Explanation:

Note: This will find both odd and even numbers, you have to change the number above to the number of your choice

For even numbers

Even number are numbers that are divisible by 2.

To print even numbers from 1 to N, traverse each number from 1.

Check if these numbers are divisible by 2.

If true, print that number.

For odd numbers

Odd number are numbers that are not divisible by 2.

To print Odd numbers from 1 to N, traverse each number from 1.

Check if these numbers are not divisible by 2.

If true, print that number

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Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc

Kipish [7]

Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, $t_{A} = 100 ps$

$t_{A} = 150 ps$

No. of cycles per instructions, $n_{A} = 2.0$

$n_{B} = 1.0$

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, $f_{A}$ = 2.0 I

CPU clock cycle, $f_{B}$ = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = $CPU clock cycle\times clock time$

$T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps$

$T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps$

Thus B is faster than A

Now,

$\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}$

$\frac{Performance of A}{Performance of B} = \frac{200}{150}$

Performance of B is 1.33 times that of A

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2 years ago

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Consider the following language:

VMariaS [17]

L is a decidable language because the Turing machine accepts it.

L is a recognizable language if TM M recognizes it.

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A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,

Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.

So, L is a decidable language because the Turing machine accepts it.

L is a recognizable language if TM M recognizes it.

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1 year ago

#Write a function called is_composite. is_composite should #take as input one integer. It should return True if the #integer is

malfutka [58]

Answer:

// A optimized school method based C++ program to check

// if a number is composite.

#include <bits/stdc++.h>

using namespace std;

bool isComposite(int n)

{

// Corner cases

if (n <= 1) return false;

if (n <= 3) return false;

// This is checked so that we can skip

// middle five numbers in below loop

if (n%2 == 0 || n%3 == 0) return true;

for (int i=5; i*i<=n; i=i+6)

if (n%i == 0 || n%(i+2) == 0)

return true;

return false;

}

// Driver Program to test above function

int main()

{

isComposite(11)? cout << " true\n": cout << " false\n";

isComposite(15)? cout << " true\n": cout << " false\n";

return 0;

}

Explanation:

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2 years ago

Write a Python program that uses function(s) for writing to and reading from a file:

swat32

import random

def random_number_file_writer(nums):

f = open("random.txt", "w")

i = 0

while i < nums:

f.write(str(random.randint(1,500))+"\n")

i += 1

f.close()

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f = open("random.txt", "r")

total = 0

count = 0

for x in f.readlines():

total += int(x)

count += 1

print("The total of the numbers is "+str(total))

print("The number of random numbers read from the file is "+str(count))

def main():

random_number_file_writer(int(input("How many random numbers do you want to generate? ")))

random_number_file_reader()

main()

I hope this helps!

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3 years ago

Choose all the answers that apply.

den301095 [7]

[1] is false, because we are talking about light reaching Earth's surface as a whole, and not in one specific place.

[2] is false, because even if it was in the middle of the night, the other side of the world will be recieving pretty much just as much light as you did the following day.

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[4] is false, because wind doesn't affect how light travels.

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Write a c++ program to print even numbers from 1 to 20​

Write a c++ program to print even numbers from 1 to 20