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viktelen [127]
3 years ago
8

Any help will be greatly appreciated thanks

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

2

Step-by-step explanation:

There are 4 x's at 1 mile so he took 4   1 mile hikes

There are 2 x's at 1 1/4 mile so he  took 2  1 1/4 mile hikes

We want to know how many more 1 mile hikes than 1 1/4 mile hikes

4 -2 = 2

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total distance covered = distance covered x time taken

<h3>=0.9×4=3.6km</h3>
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Which number when multiplied by3/8 gives 1/2
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Step-by-step explanation:

8/6 x 3/8 is 24/48 which can be reduced several times to the lowest it can be which is 1/2.

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A) yes<br> Or<br> B) no<br><br> I need to now which it’s is
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Step-by-step explanation:

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A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr
Gre4nikov [31]

Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

4 0
3 years ago
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