Answer:
C
Step-by-step explanation:
Use a quadratic equation regression calculator.
Plugging in all the points, the equation should come somewhere close to
Which is answer choice C.
Sadie is saving her money to buy a new pony, which costs $600. She has already saved $75. She earns $50 per week working at the
1 answer:
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Answer:
80.
81. Each apple cost $0.50
82. One pound of chocolate = $3
Step-by-step explanation:
80.
Let sold of 1 senior citizen ticket be "s", and
cost of 1 child ticket be "c"
First Day, 4 senior citizen ticket and 5 child tickets sold, equaled $46, so the equation we can write is:
Second Day, 3 senior citizen ticket and 1 child ticket sold, equaled $22, so the equation we can write is:
So, the system of equation (2 equations) written above can be solved simultaneously to find our answer.
81.
Let price of 1 apple be "a" and price of 1 banana be "b"
Since 3 apples and 2 banana cost $2, so we can write:
3a + 2b = 2
Then,
4 apples and 4 bananas cost $3, so we can write:
4a + 4b = 3
We can solve for the variable b in equation 1. Shown below:
Now we put this value of b into equation 2 and solve for cost of 1 apple, a. Shown below:
So each apples cost $0.5
82.
Let 1 pound of chocolate be cost "c"
Let 1 pound of peanut be cost "p"
4 lb of chocolate and 2 lb of peanut = $16, thus we can write:
4c + 2p = 16
Next,
2 lb of chocolate and 3 lb of peanut costed $12, so we can write:
2c + 3p = 12
We solve first equation for p:
Now, we put this expression for p into equation 2 and solve for c:
So, 1 pound of chocolates cost $3
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = .... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = .... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
=
+
,
x = ... And
squared is 11, making the area of this square 11 units².