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NNADVOKAT [17]
4 years ago
5

At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50° Celsius. Thi

s causes the cake to cool and the temperature difference loses (1/5) of it's value every minute.
Write a function that gives the temperature difference in degrees Celsius, D(t), t minutes after the cake was put in the cooler.
Mathematics
2 answers:
Simora [160]4 years ago
5 0

Answer:: D(t)= 50(4/5)^t

Step-by-step explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).

If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.

tankabanditka [31]4 years ago
5 0

Answer:

See answer below

Step-by-step explanation:

Hi there,

The prompt is trying to showcase exponential functions, and specifically exponential <em>decay</em>, where over the course of the independent variable (time in this example) the dependent variable (temp difference) exponentially drops.

To start, when a math prompt says something like "at the moment xyz begins" it usually means time zero. Thus, we have 1 point already, the y-intercept:

D(0)= 50 \ C°

Now, we notice that it says it "loses 1/5 of its <em>original </em>value every minute" which is code for exp. decay.  So, to account for this, the remaining value is just b = 1 - 0.2 = 0.8.

Exponential Decay formula:

f(x) = a (1-r)^x  where a is a constant, and constant r < 1

D(t) = 50 * (0.8)^t \ C°    where t is in minutes

thanks,

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